Materials:
Procedure:
The exercises below cover some fairly simple examples of determining recurrence interval. They should provide you with a good idea of how valuable the concept can be in risk assessment, and of a few of the problems associated with determining and correctly applying recurrence intervals in fault studies.
Exercise 1
A Hypothetical Fault Study
Imagine you belong to a group of geologists studying the (hypothetical) Salt Wash fault, a moderate-sized, pure strike-slip fault in the Mojave. Through your studies of the fault's history, you have determined that the fault has experienced 1.4 km of right-lateral slip in the past 5.0 million years. You have also discovered evidence that the most recent major rupture occurred approximately 400 years ago, and caused the fault to slip 2.1 meters.
Now you must report your findings and draw a few conclusions based on the evidence you've uncovered. Thus, using the information above, answer the following questions:
Compute a likely recurrence interval, using the data
from the last major rupture. While this may seem like a very long
repeat time, it is actually quite normal for real-life right-lateral
faults in the Mojave.
Given the time of the previous rupture and your calculation from question #2, do you think your findings would worry or reassure those people who live very close to the surface trace of the Salt Wash fault?
Exercise 2
The San Andreas Fault
Studies at Pallett Creek and other locations along the Mojave section of the San Andreas fault have revealed a rough chronology for that section of the fault over the last 1500 years -- much longer than that covered by historic reports and records.
A compilation of this data is shown in the table below.
|
Preferred Event Date |
Possible Date Range |
Years Until Next Event |
|---|---|---|
|
January 9, 1857 December 8, 1812 1480 A.D. 1346 A.D. 1100 A.D. 1048 A.D. 997 A.D. 797 A.D. 734 A.D. 671 A.D. before 529 A.D. |
January 9, 1857 December 8, 1812 1465 - 1495 A.D. 1329 - 1363 A.D. 1035 - 1165 A.D. 1015 - 1081 A.D. 981 - 1013 A.D. 775 - 819 A.D. 721 - 747 A.D. 658 - 684 A.D. ??? - 529 A.D. |
greater than 141 44.08 332 134 246 52 52 200 63 63 greater than 142 |
According to this average recurrence interval, is the Mojave
section of the San Andreas fault at Pallett Creek
due, not yet due, or well overdue, for a major rupture?
Looking back at the table, note the difference between
the shortest interval and the longest. How much greater than the
apparent recurrence interval is the longest interval between events?
How much smaller is the shortest interval? Does this give you more or less
confidence about your answer to question #2 (above)?
If you have a good eye for patterns, you may have noticed
something intriguing about the data above. Study it carefully.
Can you see how long rupture
intervals (greater than or equal to 200 years) seem to divide the table
into a pattern where one or two short rupture intervals are followed
by a much longer interval, which is followed again by one or two short
intervals, and so on? The effect is especially easy to pick out
if you make a graph of the data in the second column, above. Using the
graph template and instructions provided
(you will either need to print out the template, or draw a copy by hand),
construct this graph now. Then come back to answer the last question.
With your graph completed, can you now see how there might
be a long-period pattern of clusters and gaps in the recurrence
of earthquakes at Pallett Creek? If such a pattern can be believed,
then, given that over 140 years have passed since the last earthquake
ruptured this area, is it more likely that we are currently in a gap,
or a cluster? (In other words, how long is a typical "gap", as opposed
to the average time between earthquakes in a "cluster"?) Does this support
or oppose the first conclusion you came to (in question #2)?
No one is sure whether the idea hinted at by your graph is true. This example should show you, in any case, how taking a closer look at recurrence interval data can be more useful than simply doing an average calculation. In this case, if there is a larger pattern, it might occur because the San Andreas fault seems to act as a series of smaller, connected fault segments. Perhaps one segment can influence the timing of the ruptures on adjacent segments? This may be true, but as noted before, no one is certain.
Table data from:
Sieh, K., Stuiver, M. and Brillinger, D. (1989). A More Precise
Chronology of Earthquakes produced by the San Andreas Fault in Southern
California. Journal of Geophysical Research, Vol. 94,
No. B1, pp. 603-623.
Exercise 3
Longer Fault = Longer Recurrence Interval?
Very long faults with high slip rates (like the San Andreas fault in southern California) probably seem the most worrisome -- that is, potentially dangerous -- of faults. This makes sense, given that they are very active, and capable of producing large earthquakes. However, the average slip of a very long fault rupture will be much greater than the average slip of a shorter rupture. Think about the significance of that fact, in terms of recurrence intervals, as you work through the exercise below.
|
Fault segment: Length: Slip Rate: Selected Rupture: Average Slip: Magnitude: |
San Andreas (Mojave) 250 km 35 mm/yr January 9, 1857 Mw 8.0 (approx.) |
Imperial (north half) 30 km 20 mm/yr October 15, 1979 Mw 6.4 |
Now, using the information above and your previous studies, compute the approximate rupture intervals for these fault segments.
Which segment would rupture more often? Does this example
make clear how the slip rate of a fault should not be the only
measure of how active (in producing damaging earthquakes) it is?
(Keep in mind, though, that both faults in the example above have
very high slip rates.)
As you've just seen above, more slip needs to accumulate for a very long fault rupture to occur than is needed to produce a rupture of shorter length, and this additional accumulation requires more time. While the long rupture will produce a very strong earthquake (greater than magnitude 7 or 8), the shorter rupture can still produce a damaging earthquake (greater than magnitude 6). Thus, if the faults responsible for these ruptures have roughly the same slip rate, the fault experiencing the shorter ruptures will rupture more often. Though the earthquakes produced by these shorter ruptures will not be as severe as those of a longer rupture, they can still be damaging. In this light, which of two such faults should really be considered the more hazardous? The answer to that is entirely dependent upon your outlook.